R S AGGARWAL CBSE CLASS 10 MATHS CHAPTER 5 SOLUTION IN PDF | ARITHMETIC PROGRESSION CLASS 10 MATHS R S AGGARWAL BOOK CHAPTER 5 SOLUTION

R S AGGARWAL CBSE CLASS 10 MATHS CHAPTER 5 SOLUTION IN PDF |
ARITHMETIC PROGRESSION CLASS 10 MATHS R S AGGARWAL BOOK CHAPTER 5 SOLUTION IN PDF

In this article we are provide complete solution of chapter 5 class 10 maths of R S Aggarwal book.this solution helpful to cbse board class 10 students.

Important formula list of arithmetic progression.

let first term of an AP=a, common difference=d ,

total number of term=n, last term=l

1. nth term of an AP=a+(n-1)d

2. last term of an AP , l=a+(n-1)d

3.nth term from end =l-(n-1)d

4.sum of n term of an AP
Sn= n/2[2a+(n-1)d]
Sn =n/2 [a+l]
5. first three terms of an AP are a-d , a ,a+d
6.first four terms of an AP are a-3d , a-d ,a+d ,a+3d
7.if a1 , a2 ,a3 are in an AP.then common difference are equal

a2-a1 =a3-a2

SOME IMPORTANT FORMULA.

मान लीजिए किसी समान्तर श्रेणी का प्रथम पद = a, सार्व अंतर = d , पदों की कुल संख्या = n, अंतिम पद = l

1. समान्तर श्रेणी का nवाँ पद=a+(n-1)d

2. किसी समान्तर श्रेणी का अंतिम पद, l=a+(n-1)d

3.समान्तर श्रेणी का अंत से n वां पद =l-(n-1)d

4. किसी समान्तर श्रेणी के n पदों का योग

Sn = n/2[2a+(n-1)d]

Sn =n/2 [a+l]

5. किसी समान्तर श्रेणी के प्रथम तीन पद हैं a-d , a ,a+d

6. समान्तर श्रेणी के पहले चार पद हैं a-3d , a-d ,a+d ,a+3d

7.यदि a1, a2, a3 एक AP में हैं तो सार्व अंतर बराबर हैं a2-a1 =a3-a2

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R S AGGARWAL CBSE CLASS 10 MATHS CHAPTER 5 SOLUTION IN PDF | ARITHMETIC PROGRESSION CLASS 10 MATHS R S AGGARWAL BOOK CHAPTER 5 SOLUTION